7x^2+12x-4=-3x

Solution for 7x^2+12x-4=-3x equation:

7x^2+12x-4=-3x

We move all terms to the left:

7x^2+12x-4-(-3x)=0

We get rid of parentheses

7x^2+12x+3x-4=0

We add all the numbers together, and all the variables

7x^2+15x-4=0

a = 7; b = 15; c = -4;
Δ = b2-4ac
Δ = 152-4·7·(-4)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{337}}{2*7}=\frac{-15-\sqrt{337}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{337}}{2*7}=\frac{-15+\sqrt{337}}{14}
$